MATH SOLVE

3 months ago

Q:
# When rolling two six-sided number cubes, what is the probability of getting a sum of at least 5? 5/18 1/3 13/18 5/6

Accepted Solution

A:

The sample space for two six sided cubes =
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now the favourable events are those where the sum is greater than or equal to 5.It means (1,4) (1,5) (1,6) (2,3) (2,4) (2,5) (2,6) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

It meansfavourable events = 30and total possible events = 36

So probability = 30/36 Β = 5/6 Hence 4th option is the correct one.

Now the favourable events are those where the sum is greater than or equal to 5.It means (1,4) (1,5) (1,6) (2,3) (2,4) (2,5) (2,6) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

It meansfavourable events = 30and total possible events = 36

So probability = 30/36 Β = 5/6 Hence 4th option is the correct one.